Here’s a color code to resistance calculator (don’t trust my memory)…
https://en.wikipedia.org/wiki/Electronic_color_code
I’m somewhat confused by your color bands… are these 1% resistors? I’d expect a 5th band for tolerance, but let’s move along…
Let’s just map it out anyway…
Let’s suppose the final band is the number of extra zeros…
470R is yellow (4), violet (7), black (0), black(0). => 470 (zero extra zeroes)
2.2M is red (2), red (2), black (0), yellow (4) => 2,200,000 (4 extra zeroes)
68k is blue (6), silver (probably grey) (8), black (0), red (2) => 68,000 (2 extra zeroes)
So those values do look correct.
If you have a voltmeter which can read ohms, it would be good to double check these values.
Next let’s look at the currents flowing in the circuit.
I(R2) => (9.44 – 1.44)/68000 = 0.000117647
I(R1) => (1.44 – 0.61)/2,200,000 = 0.000000377
I(R3) => (0.05 – 0)/470 = 0.000106383
It doesn’t quite add up, but the 0.05 reading isn’t very accurate, so I shouldn’t add more units of precision than are really called for. I’ll conclude that these values are reasonable. What I was looking for was I(R2) = I(R1) + I(R3). The current in R2 goes into the collector and the base (via R1). The current coming out of the emitter should be the sum of the base and collector currents. I don’t see anything obviously wrong here.
The ratio of the collector current to base current is I(R2)/I(r1) which comes out to about 312. I think this is a reasonable value for a 2N3904 (but I didn’t look it up).
Up to now this has all been fairly precise. Now I’m just going to guess.
See if reducing the value of R1 to 1.0 Meg makes any difference. That will increase the base current which will increase the collector current too. It may also saturate the transistor (Vce going to about 0.3 volts), but since this circuit is supposed to generate distortion I am not going to worry about that.
I don’t have any specific experience with this circuit. If we don’t get somewhere soon I may just breadboard it myself (now where is all that stuff)…
Looked at your breadboard photos. Don’t see anything obviously wrong there.
What are you running this into to listen to it? A small load (anything much less than 68k) will reduce the gain. This circuit has tons of gain but for example if you ran it into an 8 ohm speaker, the gain would be greatly reduced.
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